In a coil of self-inductance 0.5 , H,the curr | vedclass

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(C) The formula for the induced $e.m.f.$ in a coil due to self-induction is given by $e = L \frac{di}{dt}$.Given:Self-inductance $L = 0.5 \, H$.Change

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$2.5$

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(C) The formula for the induced $e.m.f.$ in a coil due to self-induction is given by $e = L \frac{di}{dt}$.Given:Self-inductance $L = 0.5 \, H$.Change in current $\Delta i = 10 \, A - 0 \, A = 10 \, A$.Time interval $\Delta t = 2 \, s$.The rate of change of current is $\frac{\Delta i}{\Delta t} = \frac{10 \, A}{2 \, s} = 5 \, A/s$.Substituting these values into the formula:$e = 0.5 \, H 	imes 5 \, A/s = 2.5 \, V$.Therefore,the generated $e.m.f.$ is $2.5 \, V$.

In a coil of self-inductance $0.5 \, H$,the current varies at a constant rate from $0 \, A$ to $10 \, A$ in $2 \, s$. The $e.m.f.$ generated in the coil is ... $V$.

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