In a coil of resistance $10\,\Omega$,the induced current developed by changing magnetic flux through it is shown in the figure as a function of time. The magnitude of change in flux through the coil in weber is:

In the given circuit,when does the lamp become momentarily bright?

The circuit shown in the figure contains an inductor $L = 25 \text{ mH}$, a capacitor $C_0 = 10 \text{ } \mu\text{F}$, a resistor $R_0 = 5 \text{ } \Omega$ and an ideal battery of $20 \text{ V}$. The circuit also contains two keys $K_1$ and $K_2$. Initially, both the keys are open and there is no charge on the capacitor. At an instant, key $K_1$ is closed and immediately after this, the current in $R_0$ is found to be $I_1$. After a long time, the current attains a steady state value $I_2$. Thereafter, $K_2$ is closed and simultaneously $K_1$ is opened, and the voltage across $C_0$ oscillates with amplitude $V_0$ and angular frequency $\omega_0$. Match the quantities mentioned in $List-I$ with their values in $List-II$ and choose the correct option.

$List-I$	$List-II$
$(P)$ The value of $I_1$ in Ampere is	$(1)$ $0$
$(Q)$ The value of $I_2$ in Ampere is	$(2)$ $2$
$(R)$ The value of $\omega_0$ in kilo-radians/s is	$(3)$ $4$
$(S)$ The value of $V_0$ in Volt is	$(4)$ $20$
	$(5)$ $200$

$A$ square loop of side $12 \; cm$ with its sides parallel to $X$ and $Y$ axes is moved with a velocity of $8 \; cm \, s^{-1}$ in the positive $x$-direction in an environment containing a magnetic field in the positive $z$-direction. The field is neither uniform in space nor constant in time. It has a gradient of $10^{-3} \; T \, cm^{-1}$ along the negative $x$-direction (that is, it increases by $10^{-3} \; T \, cm^{-1}$ as one moves in the negative $x$-direction), and it is decreasing in time at the rate of $10^{-3} \; T \, s^{-1}$. Determine the direction and magnitude of the induced current in the loop if its resistance is $4.50 \; m\Omega$.

Shown in the figure is a circular loop of radius $r$ and resistance $R$. $A$ variable magnetic field of induction $B = B_0 e^{-t}$ is established inside the coil. If the key $K$ is closed,the electrical power developed right after closing the switch is equal to

In $SI$,Henry is the unit of