The area of a sector formed by a $12\,cm$ long arc in a circle with radius $12\,cm$ is $\ldots \ldots \ldots . . cm ^{2}$.
The circumference of a circle with radius $8.4\,cm$ is $\ldots \ldots \ldots \ldots cm$.
As shown in the diagram, rectangle $ABCD$ is inscribed in a circle. If $AB =8 \,cm$ and $BC =6\, cm ,$ find the area of the shaded region in the diagram. $(\pi=3.14)$ (in $cm^2$)
In $\odot( O ,\, 5.6), \overline{ OA }$ and $\overline{ OB }$ are radii perpendicular to each other. Then, the difference of the area of the minor sector formed by minor $\widehat{ AB }$ and the corresponding minor segment is $\ldots \ldots \ldots \ldots cm ^{2}$.
In $Fig.$ a circle is inscribed in a square of side $5 \,cm$ and another circle is circumscribing the square. Is it true to say that area of the outer circle is two times the area of the inner circle? Give reasons for your answer.