In a circle with radius $6.3\, cm ,$ a minor arc subtends an angle of measure $40$ at the centre. The area of the minor sector corresponding to that arc is $\ldots \ldots cm^{2}$.
Find the area of the shaded region in $Fig.$ where arcs drawn with centres $A , B , C$ and $D$ intersect in pairs at mid-points $P , Q , R$ and $S$ of the sides $AB , BC,$ $CD$ and $DA ,$ respectively of a square $ABCD$ (Use $\pi=3.14)$ (in $cm ^{2}$)
Is it true to say that area of a segment of a circle is less than the area of its corresponding sector? Why?
The length of the minute hand of a clock is $14 \,cm$. Find the area of the region swept by it between $10.10\, AM$ to $10.30 \,AM.$
In $\odot( O ,\, 5.6), \overline{ OA }$ and $\overline{ OB }$ are radii perpendicular to each other. Then, the difference of the area of the minor sector formed by minor $\widehat{ AB }$ and the corresponding minor segment is $\ldots \ldots \ldots \ldots cm ^{2}$.