In a circle with centre $P$,$AB$ is a diameter and $ABCD$ is a cyclic quadrilateral. If $\angle ADC = 150^{\circ}$,then find $\angle BAC$. (in $^{\circ}$)

  • A
    $60$
  • B
    $90$
  • C
    $40$
  • D
    $120$

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