In a certain town,40% of the people have brow | vedclass

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(B) Let $A$ be the event that a person has brown hair and $B$ be the event that a person has brown eyes.Given:$P(A) = 40/100 = 0.4$$P(B) = 25/100 = 0.

Vedclass · Accepted Answer

$3/8$

Vedclass · Answer

(B) Let $A$ be the event that a person has brown hair and $B$ be the event that a person has brown eyes.Given:$P(A) = 40/100 = 0.4$$P(B) = 25/100 = 0.25$$P(A \cap B) = 15/100 = 0.15$We need to find the conditional probability $P(B|A)$,which is the probability that a person has brown eyes given that they have brown hair.The formula for conditional probability is $P(B|A) = \frac{P(A \cap B)}{P(A)}$.Substituting the values:$P(B|A) = \frac{0.15}{0.40} = \frac{15}{40} = \frac{3}{8}$.Thus,the probability is $3/8$.

$Face$	$1$	$2$	$3$	$4$	$5$	$6$
$P(F)$	$0.1$	$0.24$	$0.19$	$0.18$	$0.15$	$0.14$

In a certain town,$40\%$ of the people have brown hair,$25\%$ have brown eyes,and $15\%$ have both brown hair and brown eyes. If a person selected at random from the town has brown hair,what is the probability that they also have brown eyes?

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