In a box containing 100 eggs,10 eggs are rott | vedclass

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(D) Total number of eggs = $100$. Number of rotten eggs = $10$. Number of fresh eggs = $100 - 10 = 90$. Probability of picking a fresh egg $(p)$ = $\f

Vedclass · Accepted Answer

$(\frac{9}{10})^5$

Vedclass · Answer

(D) Total number of eggs = $100$. Number of rotten eggs = $10$. Number of fresh eggs = $100 - 10 = 90$. Probability of picking a fresh egg $(p)$ = $\frac{90}{100} = \frac{9}{10}$. Since the sampling is done with replacement,the probability of picking a fresh egg remains constant for each draw. We need to find the probability that in a sample of $n = 5$ eggs,none are rotten,which means all $5$ eggs must be fresh. Probability = $p 	imes p 	imes p 	imes p 	imes p = p^5$. Probability = $(\frac{9}{10})^5$.

In a box containing $100$ eggs,$10$ eggs are rotten. The probability that out of a sample of $5$ eggs none is rotten if the sampling is with replacement is

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