In a basic aqueous solution,if the concentrat | vedclass

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(A) The $pOH$ of a solution is defined by the formula: $pOH = -\log_{10}[OH^-]$.Since $pOH$ is inversely proportional to the logarithm of the hydroxid

Vedclass · Accepted Answer

It decreases.

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(A) The $pOH$ of a solution is defined by the formula: $pOH = -\log_{10}[OH^-]$.Since $pOH$ is inversely proportional to the logarithm of the hydroxide ion concentration,as the concentration of $[OH^-]$ increases,the value of $\log_{10}[OH^-]$ also increases.Because of the negative sign in the formula,an increase in the value of $\log_{10}[OH^-]$ leads to a decrease in the $pOH$ value.Therefore,if the concentration of $[OH^-]$ increases,the $pOH$ decreases.

In a basic aqueous solution,if the concentration of $[OH^-]$ increases,what happens to the $pOH$?

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