In a S_N2 substitution reaction of the type R | vedclass

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(B) In $S_N2$ reactions,the rate of reaction is inversely proportional to the steric hindrance around the carbon atom undergoing substitution. As the

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$CH_3-CH_2-Br$

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(B) In $S_N2$ reactions,the rate of reaction is inversely proportional to the steric hindrance around the carbon atom undergoing substitution. As the size of the alkyl group increases or branching increases near the reaction center,the rate decreases. Comparing the given primary alkyl halides: $(a)$ $CH_3-C(CH_3)_2-CH_2-Br$ (neopentyl bromide) has significant steric hindrance due to the bulky tert-butyl group. $(b)$ $CH_3-CH_2-Br$ (ethyl bromide) has the least steric hindrance. $(c)$ $CH_3-CH_2-CH_2-Br$ (n-propyl bromide) has more steric hindrance than ethyl bromide. $(d)$ $CH_3-CH(CH_3)-CH_2-Br$ (isobutyl bromide) has more steric hindrance than ethyl bromide. Therefore,$CH_3-CH_2-Br$ shows the highest relative rate.

In a $S_N2$ substitution reaction of the type $R-Br + Cl^- \xrightarrow{DMF} R-Cl + Br^-$,which one of the following has the highest relative rate?

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