In a $\triangle ABC$,if $b=10$,$a \cos^2 \frac{C}{2} + c \cos^2 \frac{A}{2} = 15$,and the area of the triangle is $15\sqrt{3}$ sq. units,then $\cot \frac{B}{2} =$

  • A
    $\frac{3}{2}$
  • B
    $\frac{1}{2}$
  • C
    $\frac{2}{\sqrt{3}}$
  • D
    $\frac{5}{\sqrt{3}}$

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