In a $U$-tube,the liquid level stands at the same level when it is at rest. When the $U$-tube is accelerated towards the right with acceleration $a$,as shown in the figure,the difference $h$ between the levels of the two arms is:

  • A
    $\frac{aL}{2g}$
  • B
    $\frac{gL}{2a}$
  • C
    $\frac{gL}{a}$
  • D
    $\frac{aL}{g}$

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