In a $U-$ tube, the liquid level stands at same level when it is at rest. When $U-$ tube is accelerated towards right, as shown in figure, the difference $h$  between level of two arms will be 

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  • A

    $\frac {aL}{2g}$

  • B

    $\frac {gL}{2a}$

  • C

    $\frac {gL}{a}$

  • D

    $\frac {aL}{g}$

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