In a CE transistor amplifier,the audio signal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The output voltage $V_{out}$ in a $CE$ transistor amplifier is given by the product of the output current and the load resistance.$V_{out} = I_c \

Vedclass · Accepted Answer

$10\, mV$

Vedclass · Answer

(D) The output voltage $V_{out}$ in a $CE$ transistor amplifier is given by the product of the output current and the load resistance.$V_{out} = I_c 	imes R_L$Given $V_{out} = 2\, V$ and $R_L = 2\, k\Omega = 2000\, \Omega$,the collector current is:$I_c = \frac{V_{out}}{R_L} = \frac{2}{2000} = 10^{-3}\, A = 1\, mA$.We know the current amplification factor $\beta = \frac{I_c}{I_b}$. Thus,the base current is:$I_b = \frac{I_c}{\beta} = \frac{1\, mA}{100} = 0.01\, mA = 10\, \mu A$.The input signal voltage $V_{in}$ is related to the base current and base resistance $R_i$ by Ohm's law:$V_{in} = I_b 	imes R_i$Given $R_i = 1\, k\Omega = 1000\, \Omega$:$V_{in} = (10 	imes 10^{-6}\, A) 	imes (1000\, \Omega) = 0.01\, V = 10\, mV$.

In a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2\, k\Omega$ is $2\, V$. If the base resistance is $1\, k\Omega$ and the current amplification factor $(\beta)$ of the transistor is $100$,the input signal voltage is:

Similar Questions

$A$ tension of $20 ~N$ is applied to a copper wire of cross-sectional area $0.01 ~cm^2$. The Young's modulus of copper is $1.1 \times 10^{11} ~N/m^2$ and the Poisson's ratio is $0.32$. The decrease in the cross-sectional area of the wire is:

Widal test is used for the diagnosis of

$A$ point is moving on $y=4-2x^2$. The $x$-coordinate of the point is decreasing at the rate of $5 \text{ units/s}$. Then,the rate at which the $y$-coordinate of the point is changing when the point is at $(1,2)$ is

$A$ particle is moving on a circular path of radius $r$ with uniform speed $v$. The change in velocity when the particle moves from $P$ to $Q$ is $(\angle POQ = 40^\circ)$.

For a reversible reaction $A \rightleftharpoons B$,which one of the following statements is wrong from the given energy profile diagram?

Vedclass Test Series

Exam Paper Generator

Online Exam Module