In S_{N}2 reactions,the correct order of reac | vedclass

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(B) The rate of $S_{N}2$ reactions is inversely proportional to the steric hindrance around the electrophilic carbon atom.As the number of alkyl group

Vedclass · Accepted Answer

$CH_3Cl > CH_3CH_2Cl > (CH_3)_2CHCl > (CH_3)_3CCl$

Vedclass · Answer

(B) The rate of $S_{N}2$ reactions is inversely proportional to the steric hindrance around the electrophilic carbon atom.As the number of alkyl groups attached to the carbon bearing the halogen increases,the steric crowding increases,which hinders the approach of the nucleophile.The order of reactivity for alkyl halides in $S_{N}2$ reactions is: $Methyl \ halide > Primary \ (1^{\circ}) \ halide > Secondary \ (2^{\circ}) \ halide > Tertiary \ (3^{\circ}) \ halide$.Comparing the given compounds:$CH_3Cl$ (Methyl halide) > $CH_3CH_2Cl$ (Primary) > $(CH_3)_2CHCl$ (Secondary) > $(CH_3)_3CCl$ (Tertiary).Therefore,the correct order is $CH_3Cl > CH_3CH_2Cl > (CH_3)_2CHCl > (CH_3)_3CCl$.

In $S_{N}2$ reactions,the correct order of reactivity for the following compounds:

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