In the _{88}Ra^{226} nucleus,there are | vedclass

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(B) The notation for a nucleus is given by $_Z{X^A}$,where $Z$ is the atomic number (number of protons) and $A$ is the mass number (total number of pr

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$138$ neutrons and $88$ protons

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(B) The notation for a nucleus is given by $_Z{X^A}$,where $Z$ is the atomic number (number of protons) and $A$ is the mass number (total number of protons and neutrons).For the nucleus $_{88}Ra^{226}$:Atomic number $Z = 88$,which represents the number of protons.Mass number $A = 226$.The number of neutrons $N$ is calculated as $N = A - Z$.$N = 226 - 88 = 138$.Therefore,there are $88$ protons and $138$ neutrons.

In the $_{88}Ra^{226}$ nucleus,there are

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