In $\triangle ABC$,if $a : b : c = 4 : 5 : 6$,then the ratio of the circumradius to its inradius is

  • A
    $16 : 7$
  • B
    $25 : 11$
  • C
    $5 : 4$
  • D
    $9 : 5$

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$III. r_3 = \frac{\Delta}{s-c}$

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