(B) The given compound is Prussian blue,which is $Fe_4[Fe(CN)_6]_3$. Comparing this with the general formula $Fe_x[Fe_y(CN)_6]_3$,we can identify the

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(B) The given compound is Prussian blue,which is $Fe_4[Fe(CN)_6]_3$. Comparing this with the general formula $Fe_x[Fe_y(CN)_6]_3$,we can identify the values of $x$ and $y$. Here,$x = 4$ and $y = 1$. Thus,the values of $x$ and $y$ are $4$ and $1$ respectively.