In Delta ABC, if a = 16, b = 24 and c = 20, t | vedclass

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(A) Given sides are $a = 16, b = 24, c = 20$.Semi-perimeter $s = \frac{a + b + c}{2} = \frac{16 + 24 + 20}{2} = \frac{60}{2} = 30$.Using the formula $

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$3/4$

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(A) Given sides are $a = 16, b = 24, c = 20$.Semi-perimeter $s = \frac{a + b + c}{2} = \frac{16 + 24 + 20}{2} = \frac{60}{2} = 30$.Using the formula $\cos \frac{B}{2} = \sqrt{\frac{s(s - b)}{ac}}$:$\cos \frac{B}{2} = \sqrt{\frac{30(30 - 24)}{16 	imes 20}}$$\cos \frac{B}{2} = \sqrt{\frac{30 	imes 6}{320}}$$\cos \frac{B}{2} = \sqrt{\frac{180}{320}} = \sqrt{\frac{18}{32}} = \sqrt{\frac{9}{16}}$$\cos \frac{B}{2} = \frac{3}{4}$.

In $\Delta ABC,$ if $a = 16, b = 24$ and $c = 20,$ then $\cos \frac{B}{2} = $

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