In PCl_{5} molecule,the angle Cl-P-Cl present | vedclass

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Question

(B) The $PCl_{5}$ molecule has a trigonal bipyramidal geometry.In this structure,three $Cl$ atoms are present in the equatorial plane,forming a trigon

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(B) The $PCl_{5}$ molecule has a trigonal bipyramidal geometry.In this structure,three $Cl$ atoms are present in the equatorial plane,forming a trigonal arrangement around the central $P$ atom.The bond angle between these equatorial $Cl-P-Cl$ bonds is $120^{\circ}$.The other two $Cl$ atoms are in the axial positions,making a $90^{\circ}$ angle with the equatorial plane and a $180^{\circ}$ angle with each other.

In $PCl_{5}$ molecule,the angle $Cl-P-Cl$ present in a plane is equal to (in $^{\circ}$)

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