In Delta ABC,the bisector of angle A intersec | vedclass

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(D) According to the Angle Bisector Theorem,if a ray bisects an angle of a triangle,then it divides the opposite side into segments that are proportio

Vedclass · Accepted Answer

$BD 	imes AC = DC 	imes AB$

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(D) According to the Angle Bisector Theorem,if a ray bisects an angle of a triangle,then it divides the opposite side into segments that are proportional to the other two sides of the triangle.In $\Delta ABC$,since $AD$ is the bisector of $\angle A$,it divides the side $BC$ such that:$\frac{BD}{DC} = \frac{AB}{AC}$By cross-multiplying the terms,we get:$BD 	imes AC = DC 	imes AB$Therefore,the correct option is $D$.

In $\Delta ABC$,the bisector of $\angle A$ intersects $\overline{BC}$ at point $D$,then

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