In Delta ABC,AB = AC and angle C = 75^{circ}, | vedclass

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(D) Given that in $\Delta ABC$,$AB = AC$.According to the property of an isosceles triangle,angles opposite to equal sides are equal.Therefore,the ang

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$75$

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(D) Given that in $\Delta ABC$,$AB = AC$.According to the property of an isosceles triangle,angles opposite to equal sides are equal.Therefore,the angle opposite to side $AB$ is $\angle C$ and the angle opposite to side $AC$ is $\angle B$.Since $AB = AC$,it follows that $\angle B = \angle C$.Given that $\angle C = 75^{\circ}$.Thus,$\angle B = 75^{\circ}$.

In $\Delta ABC$,$AB = AC$ and $\angle C = 75^{\circ}$,then find $\angle B$. (in $^{\circ}$)

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