In $\Delta ABC$,$AB = AC$ and $\angle B = 75^{\circ}$,then $\angle C = \dots$ (in $^{\circ}$)

Measure of each exterior angle of an equilateral triangle is $\ldots \ldots \ldots$ (in $^{\circ}$)

In $\Delta ABC$,$AB > BC > CA$. Write the measure of the angles of the triangle in ascending order.

"If two angles and a side of one triangle are equal to two angles and a side of another triangle,then the two triangles must be congruent." Is the statement true? Why?

Bisectors of the angles $B$ and $C$ of an isosceles triangle with $AB = AC$ intersect each other at $O$. $BO$ is produced to a point $M$. Prove that $\angle MOC = \angle ABC$.

Is it possible to construct a triangle with lengths of its sides as $4 \, cm, 3 \, cm$ and $7 \, cm$? Give reason for your answer.