In Delta PQR,angle P : angle Q : angle R = 5 | vedclass

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Question

(A) Let the angles of $\Delta PQR$ be $5x$,$2x$,and $2x$ respectively.According to the angle sum property of a triangle,the sum of all interior angles

Vedclass · Accepted Answer

$\angle P = 100^{\circ}, \angle Q = 40^{\circ}, \angle R = 40^{\circ}$

Vedclass · Answer

(A) Let the angles of $\Delta PQR$ be $5x$,$2x$,and $2x$ respectively.According to the angle sum property of a triangle,the sum of all interior angles is $180^{\circ}$.Therefore,$5x + 2x + 2x = 180^{\circ}$.$9x = 180^{\circ}$.$x = 20^{\circ}$.Now,calculating each angle:$\angle P = 5x = 5 	imes 20^{\circ} = 100^{\circ}$.$\angle Q = 2x = 2 	imes 20^{\circ} = 40^{\circ}$.$\angle R = 2x = 2 	imes 20^{\circ} = 40^{\circ}$.Thus,the angles are $100^{\circ}, 40^{\circ}, 40^{\circ}$.

In $\Delta PQR$,$\angle P : \angle Q : \angle R = 5 : 2 : 2$. Find the measure of each angle of $\Delta PQR$.

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