In $\Delta ABC$,$m \angle B = 90^{\circ}$ and $\overline{BM}$ is an altitude to the hypotenuse $\overline{AC}$. If $AM = 4$ and $CM = 6$,then $BM = \dots$

  • A
    $2$
  • B
    $\sqrt{6}$
  • C
    $2\sqrt{6}$
  • D
    $24$

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