In Na_2[Fe(CN)_5NO],sodium nitroprusside: | vedclass

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(C) In sodium nitroprusside,$Na_2[Fe(CN)_5NO]$,the complex ion is $[Fe(CN)_5NO]^{2-}$.Let the oxidation state of $Fe$ be $x$.The ligand $CN^-$ has a c

Vedclass · Accepted Answer

both are correct

Vedclass · Answer

(C) In sodium nitroprusside,$Na_2[Fe(CN)_5NO]$,the complex ion is $[Fe(CN)_5NO]^{2-}$.Let the oxidation state of $Fe$ be $x$.The ligand $CN^-$ has a charge of $-1$ and $NO$ acts as a nitrosonium ion $(NO^+)$ with a charge of $+1$.Applying the charge balance: $x + 5(-1) + 1 = -2$.$x - 5 + 1 = -2$.$x - 4 = -2$.$x = +2$.Thus,the oxidation state of $Fe$ is $+2$ and the ligand is $NO^+$. Both statements are correct.

In $Na_2[Fe(CN)_5NO]$,sodium nitroprusside:

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