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(A) In a parallel combination of resistors, the equivalent resistance is always less than the smallest individual resistance in the circuit.Since the

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Less than $2 \, \Omega$

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(A) In a parallel combination of resistors, the equivalent resistance is always less than the smallest individual resistance in the circuit.Since the smallest resistor is $2 \, \Omega$, the total resistance must be less than $2 \, \Omega$.This can be calculated using the formula for parallel resistors:$\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$$\frac{1}{R_p} = \frac{1}{2} + \frac{1}{3} + \frac{1}{5}$$\frac{1}{R_p} = \frac{15 + 10 + 6}{30} = \frac{31}{30}$$R_p = \frac{30}{31} \approx 0.967 \, \Omega$Thus, the total resistance is approximately $0.967 \, \Omega$, which is less than $2 \, \Omega$.

If you connect three resistors having values $2 \, \Omega$, $3 \, \Omega$, and $5 \, \Omega$ in parallel, will the value of total resistance be less than $2 \, \Omega$, greater than $5 \, \Omega$, or lie between $2 \, \Omega$ and $5 \, \Omega$? Explain.

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