If you are provided with three resistors of 2 | vedclass

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(C) To obtain an equivalent resistance of $4 \,\Omega$ from resistors of $2 \,\Omega$,$3 \,\Omega$,and $6 \,\Omega$:$1$. First,connect the $3 \,\Omega

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(C) To obtain an equivalent resistance of $4 \,\Omega$ from resistors of $2 \,\Omega$,$3 \,\Omega$,and $6 \,\Omega$:$1$. First,connect the $3 \,\Omega$ and $6 \,\Omega$ resistors in parallel. The equivalent resistance $R_p$ of this parallel combination is given by:$\frac{1}{R_p} = \frac{1}{3} + \frac{1}{6} = \frac{2+1}{6} = \frac{3}{6} = \frac{1}{2} \implies R_p = 2 \,\Omega$.$2$. Now,connect this parallel combination $(R_p = 2 \,\Omega)$ in series with the remaining $2 \,\Omega$ resistor.$3$. The total equivalent resistance $R_{eq}$ is:$R_{eq} = R_p + 2 \,\Omega = 2 \,\Omega + 2 \,\Omega = 4 \,\Omega$.Thus,connecting $3 \,\Omega$ and $6 \,\Omega$ in parallel and then adding $2 \,\Omega$ in series gives the desired result. Therefore,option $(C)$ is correct.

If you are provided with three resistors of $2 \,\Omega$,$3 \,\Omega$,and $6 \,\Omega$,how will you connect them to obtain an equivalent resistance of $4 \,\Omega$?

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