If we can throw a ball upto a maximum height | vedclass

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Question

$\begin{array}{l}
H = \frac{{{u^2}}}{{2g}} \Rightarrow {u^2} = 2gH\
For\,{m{maximum}}\,horizontal\,{m{distance}}\
{X_{\max }} = \frac{{{u^2}}

Vedclass · Accepted Answer

$2\,H$

Vedclass · Answer

$\begin{array}{l}
H = \frac{{{u^2}}}{{2g}} \Rightarrow {u^2} = 2gH\
For\,{m{maximum}}\,horizontal\,{m{distance}}\
{X_{\max }} = \frac{{{u^2}}}{g} = \frac{{2gH}}{g} = 2H
\end{array}$

If we can throw a ball upto a maximum height $H$, the maximum horizontal distance to which we can throw it is

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