If wattless current flows in the $AC$ circuit, then the circuit is

The equation of current in a purely inductive circuit is $i = 5 \sin (49 \pi t - 30^{\circ})$. If the inductance is $30 \, mH$,then the equation for the voltage across the inductor will be. (Let $\pi = \frac{22}{7}$)

$A$ resistor of resistance $100 \Omega$ is connected to an $AC$ source $\varepsilon = 10 \sin (250 \pi t)$. The energy dissipated as heat during $t = 0$ to $t = 1 \text{ ms}$ is approximately.

$A$ sinusoidal voltage $V(t) = 100 \sin(500t)$ is applied across a pure inductance of $L = 0.02 \, H$. The current through the coil is:

$A$ capacitor '$C$' is connected across a $DC$ source,the reactance of the capacitance will be . . . . . . .

An alternating voltage $v = 200 \sqrt{2} \sin(100 t)$ is connected to a $1 \mu F$ capacitor through an $A.C.$ ammeter. The reading of the ammeter shall be: (in $\text{ mA}$)