If water is flowing in a pipe with speed $2 \,m / s$ then its kinetic energy per unit volume is ........... $J ^2 m ^3$

According to Bernoulli's equation $\frac{P}{{\rho g}} + h + \frac{1}{2}\,\frac{{{v^2}}}{g} = {\rm{constant}}$     The terms $A, B$  and $ C$  are generally called respectively:

Water is flowing through a horizontal pipe of non-uniform cross-section. At the extreme narrow portion of the pipe, the water will have

Bernoulli’s principle is based on the law of conservation of

A train with cross-sectional area $S _{ t }$ is moving with speed $v_t$ inside a long tunnel of cross-sectional area $S _0\left( S _0=4 S _{ t }\right)$. Assume that almost all the air (density $\rho$ ) in front of the train flows back between its sides and the walls of the tunnel. Also, the air flow with respect to the train is steady and laminar. Take the ambient pressure and that inside the train to be $p _0$. If the pressure in the region between the sides of the train and the tunnel walls is $p$, then $p _0- p =\frac{7}{2 N } \rho v_{ t }^2$. The value of $N$ is. . . . .

A manometer connected to a closed tap reads $4.5 \times {10^5}$ pascal. When the tap is opened the reading of the manometer falls to $4 \times {10^5}$ pascal. Then the velocity of flow of water is ........  $m{s^{ - 1}}$