If two bodies of masses 2 ,kg and 3 ,kg are m | vedclass

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(C) Let the mass of the first body be $m_1 = 2 \,kg$ and its velocity be $\vec{v}_1 = 20 \hat{i} \,m \,s^{-1}$.Let the mass of the second body be $m_2

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$10 \,m \,s^{-1}$

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(C) Let the mass of the first body be $m_1 = 2 \,kg$ and its velocity be $\vec{v}_1 = 20 \hat{i} \,m \,s^{-1}$.Let the mass of the second body be $m_2 = 3 \,kg$ and its velocity be $\vec{v}_2 = 10 \hat{j} \,m \,s^{-1}$.The velocity of the centre of mass $\vec{v}_{cm}$ is given by the formula:$\vec{v}_{cm} = \frac{m_1 \vec{v}_1 + m_2 \vec{v}_2}{m_1 + m_2}$Substituting the values:$\vec{v}_{cm} = \frac{2(20 \hat{i}) + 3(10 \hat{j})}{2 + 3} = \frac{40 \hat{i} + 30 \hat{j}}{5} = 8 \hat{i} + 6 \hat{j} \,m \,s^{-1}$.The magnitude of the velocity of the centre of mass is:$|\vec{v}_{cm}| = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = \sqrt{100} = 10 \,m \,s^{-1}$.

If two bodies of masses $2 \,kg$ and $3 \,kg$ are moving at right angles with velocities $20 \,m \,s^{-1}$ and $10 \,m \,s^{-1}$ respectively, then the velocity of the centre of mass of the system of the two bodies is

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