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(C) For a weak acid,the degree of dissociation $\alpha$ is given by $\alpha = \sqrt{\frac{K_a}{C}}$.Since the concentration $C$ is the same for both a

Vedclass · Accepted Answer

$\alpha_1^2 K_{a_2} = \alpha_2^2 K_{a_1}$

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(C) For a weak acid,the degree of dissociation $\alpha$ is given by $\alpha = \sqrt{\frac{K_a}{C}}$.Since the concentration $C$ is the same for both acids,we have $\alpha \propto \sqrt{K_a}$.Therefore,$\frac{\alpha_1}{\alpha_2} = \sqrt{\frac{K_{a_1}}{K_{a_2}}}$.Squaring both sides,we get $\frac{\alpha_1^2}{\alpha_2^2} = \frac{K_{a_1}}{K_{a_2}}$.Cross-multiplying gives $\alpha_1^2 K_{a_2} = \alpha_2^2 K_{a_1}$.

If two acids of equimolar concentration are taken,then which option is correct?

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