If three resistors of resistance 2 ,Omega,4 , | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For resistors connected in parallel,the equivalent resistance $R_{eq}$ is given by the formula:$\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} +

Vedclass · Accepted Answer

$\frac{20}{19} \,\Omega$

Vedclass · Answer

(A) For resistors connected in parallel,the equivalent resistance $R_{eq}$ is given by the formula:$\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$Given $R_1 = 2 \,\Omega$,$R_2 = 4 \,\Omega$,and $R_3 = 5 \,\Omega$.Substituting the values:$\frac{1}{R_{eq}} = \frac{1}{2} + \frac{1}{4} + \frac{1}{5}$Taking the least common multiple $(LCM)$ of $2, 4,$ and $5$,which is $20$:$\frac{1}{R_{eq}} = \frac{10 + 5 + 4}{20} = \frac{19}{20} \,\Omega^{-1}$Therefore,the total resistance is:$R_{eq} = \frac{20}{19} \,\Omega$

If three resistors of resistance $2 \,\Omega$,$4 \,\Omega$ and $5 \,\Omega$ are connected in parallel,then the total resistance of the combination will be:

Similar Questions

For three resistors of different values connected in series,obtain the equation for equivalent resistance. From this,write the equation for $n$ resistors connected in series.

$A$ copper wire of resistance $R$ is cut into ten parts of equal length. Two pieces each are joined in series and then five such combinations are joined in parallel. The new combination will have a resistance

$10$ wires (same length,same area,same material) are connected in parallel and each has $1 \ \Omega$ resistance,then the equivalent resistance will be .............. $\Omega$.

Two resistors $R_{1} = (4 \pm 0.8) \, \Omega$ and $R_{2} = (4 \pm 0.4) \, \Omega$ are connected in parallel. The equivalent resistance of their parallel combination will be

$A$ uniform wire of resistance $20 \,\Omega$ having resistance $1 \,\Omega/m$ is bent into a circle as shown in the figure. If the equivalent resistance between $M$ and $N$ is $1.8 \,\Omega$,then the length of the shorter section is ................ $m$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module