If the Wheatstone bridge with four resistors $R_1, R_2, R_3$ and $R_4$ is balanced,then the correct expression is

  • A
    $\frac{R_2}{R_1}=\frac{R_4}{R_3}$
  • B
    $\frac{R_2}{R_3}=\frac{R_1}{R_4}$
  • C
    $R_1 R_2=R_3 R_4$
  • D
    $R_1+R_2=R_3+R_4$

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