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(B) The Zener diode is connected in parallel with the resistor $2R$. Since the Zener diode is in the breakdown region,the voltage across it is constan

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$8$

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(B) The Zener diode is connected in parallel with the resistor $2R$. Since the Zener diode is in the breakdown region,the voltage across it is constant at $9\ V$. Because the resistor $2R$ is in parallel with the Zener diode,the voltage across $2R$ is also $9\ V$. The total voltage applied across terminals $A$ and $B$ is $17\ V$. Let $V_R$ be the voltage across resistor $R$. According to Kirchhoff's voltage law,the total voltage is the sum of the voltage across $R$ and the voltage across the parallel combination of the Zener diode and $2R$. $V_{total} = V_R + V_{Zener}$ $17\ V = V_R + 9\ V$ $V_R = 17\ V - 9\ V = 8\ V$. Therefore,the potential voltage across $R$ is $8\ V$.

If the voltage between the terminals $A$ and $B$ is $17\ V$ and the Zener breakdown voltage is $9\ V$,then the potential voltage across $R$ is.......$V$.

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