If the uncertainty in velocity of electron $(\Delta v)$ is $0.1 \ m/s$,the uncertainty in its position $(\Delta x)$ is (given: $m_e = 9.1 \times 10^{-31} \ kg$)

$A$ particle of mass $25 \, g$ has an uncertainty in position of $10^{-5} \, m$. The uncertainty in velocity is ... (Planck's constant $h = 6.6 \times 10^{-34} \, J \cdot s$).

$x$ and $y$ are two moving particles. The uncertainty in the momentum of $x$ is half the uncertainty in the momentum of $y$. If the uncertainty in the position of particle $x$ is $0.05 \ \mathring{A}$,then the uncertainty in the position of particle $y$ is = .......

Based on Heisenberg's uncertainty principle,the uncertainty in the velocity of the electron to be found within an atomic nucleus of diameter $10^{-15} \ m$ is ............. $\times 10^9 \ ms^{-1}$ (nearest integer)
[Given : mass of electron $= 9.1 \times 10^{-31} \ kg$,Plank's constant $(h) = 6.626 \times 10^{-34} \ Js$ ]
(Value of $\pi = 3.14$ )

If uncertainty in the position of an electron is zero,the uncertainty in its momentum would be

The wave mechanical model of atom is based upon