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(C) Let the first term of the $G.P.$ be $a$ and the common ratio be $r$.The terms of the $G.P.$ are $a, ar, ar^2, ar^3, ar^4, \dots$Given that the thi

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$4^5$

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(C) Let the first term of the $G.P.$ be $a$ and the common ratio be $r$.The terms of the $G.P.$ are $a, ar, ar^2, ar^3, ar^4, \dots$Given that the third term is $4$,so $ar^2 = 4$.The product of the first $5$ terms is $P = a 	imes (ar) 	imes (ar^2) 	imes (ar^3) 	imes (ar^4)$.$P = a^5 	imes r^{(1+2+3+4)} = a^5 	imes r^{10}$.$P = (ar^2)^5$.Substituting the value $ar^2 = 4$,we get $P = 4^5$.

If the third term of a $G.P.$ is $4$,then the product of its first $5$ terms is:

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