If the sum of the series $20 + 19 \frac{3}{5} + 19 \frac{1}{5} + 18 \frac{4}{5} + \ldots$ up to $n^{\text{th}}$ term is $488$ and the $n^{\text{th}}$ term is negative,then:

  • A
    $n^{\text{th}}$ term is $-4 \frac{2}{5}$
  • B
    $n = 41$
  • C
    $n^{\text{th}}$ term is $-4$
  • D
    $n = 60$

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