If the standard reduction potentials for four | vedclass

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Question

(D) The standard reduction potentials $(SRP)$ are given as:
$E^\circ_{X^{+2}/X} = -1.46 \ V$
$E^\circ_{Y^{+2}/Y} = -0.36 \ V$
$E^\circ_{Z^{+2}/Z} =

Vedclass · Accepted Answer

All the above statements are correct

Vedclass · Answer

(D) The standard reduction potentials $(SRP)$ are given as:
$E^\circ_{X^{+2}/X} = -1.46 \ V$
$E^\circ_{Y^{+2}/Y} = -0.36 \ V$
$E^\circ_{Z^{+2}/Z} = 0.15 \ V$
$E^\circ_{W^{+2}/W} = -1.24 \ V$
$A$ metal with a lower (more negative) reduction potential can displace a metal with a higher (more positive) reduction potential from its salt solution.
Since $E^\circ_{X^{+2}/X} < E^\circ_{Z^{+2}/Z}$,$X$ will displace $Z^{+2}$.
Since $E^\circ_{Y^{+2}/Y} < E^\circ_{Z^{+2}/Z}$,$Y$ will displace $Z^{+2}$.
Since $E^\circ_{W^{+2}/W} < E^\circ_{Z^{+2}/Z}$,$W$ will displace $Z^{+2}$.
Therefore,all the given statements are correct.

If the standard reduction potentials for four divalent elements $X, Y, Z,$ and $W$ are $-1.46 \ V, -0.36 \ V, 0.15 \ V,$ and $-1.24 \ V$ respectively,then:

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