If the source of light used in a Young's double slit experiment is changed from red to violet:

The angular width of a fringe in a double slit experiment is found to be $0.2^{\circ}$ on a screen $1 \ m$ away. The wavelength of light used is $600 \ nm$. What is the change in the angular width of the fringe if the entire measurement system is immersed in water (in $^{\circ}$)? (Use refractive index of water as $\mu = \frac{4}{3}$)

In a two-slit experiment with monochromatic light, fringes are obtained on a screen placed at some distance from the slits. If the screen is moved by $5 \times 10^{-2} \, m$ towards the slits, the change in fringe width is $3 \times 10^{-5} \, m$. If the separation between the slits is $10^{-3} \, m$, the wavelength of light used is: (in $\text{Å}$)

In a $YDSE$,the central bright fringe can be identified:

In a Young's double slit experiment,the separation between the slits is $0.15 \; mm$. In the experiment,a source of light of wavelength $589 \; nm$ is used and the interference pattern is observed on a screen kept $1.5 \; m$ away. The separation between the successive bright fringes on the screen is $...... \; mm$. (in $.9$)

In a Young's double-slit experiment,the slit separation is $0.589 \, mm$ using sodium light. What is the angular separation between the third maximum and the central maximum? $(\lambda = 589 \, nm)$