If the resistance of a conductor is doubled,t | vedclass

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(A) According to Ohm's Law,$V = IR$,where $V$ is potential difference,$I$ is current,and $R$ is resistance.Rearranging for current,we get $I = V/R$.If

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(A) According to Ohm's Law,$V = IR$,where $V$ is potential difference,$I$ is current,and $R$ is resistance.Rearranging for current,we get $I = V/R$.If the resistance $R$ is doubled $(R' = 2R)$ while the potential difference $V$ remains constant,the new current $I'$ becomes $I' = V/(2R) = (1/2) 	imes (V/R) = I/2$.Therefore,the current is halved.

If the resistance of a conductor is doubled,the current is halved.

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