If the rate of change in electric flux between the plates of a capacitor is $9 \pi \times 10^3 \text{ Vm s}^{-1}$,then the displacement current inside the capacitor is (in $\mu \text{A}$)

  • A
    $0.25$
  • B
    $0.36$
  • C
    $3.14$
  • D
    $4$

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Similar Questions

Which of the following options represents the Ampere-Maxwell Law?

Match List-$I$ with List-$II$ and choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
| :--- | :--- |
| $A$. Gauss's law of magnetostatics | $I$. $\oint \vec{E} \cdot d\vec{a} = \frac{1}{\epsilon_0} \int \rho dV$ |
| $B$. Faraday's law of electromagnetic induction | $II$. $\oint \vec{B} \cdot d\vec{a} = 0$ |
| $C$. Ampere's law | $III$. $\oint \vec{E} \cdot d\vec{l} = -\frac{d}{dt} \int \vec{B} \cdot d\vec{a}$ |
| $D$. Gauss's law of electrostatics | $IV$. $\oint \vec{B} \cdot d\vec{l} = \mu_0 I$ |

Write inferences from Maxwell's equations.

Which of the following statements is true for displacement current?

$A$ parallel plate capacitor is charged to $60\,\mu C$. Due to a radioactive source,the plate loses charge at the rate of $1.8 \times 10^{-8}\, C/s$. The magnitude of the displacement current is:

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