If the radius of an anion is double that of a cation,the coordination number of the cation and the type of hole occupied are respectively:

The ratio of the number of atoms present in a simple cubic,body-centered cubic,and face-centered cubic unit cell is,respectively:

For an ionic crystal $A^{+}B^{-}$ with coordination number $6$,the radius ratio will be

The structure of $TlCl$ is similar to $CsCl$. What would be the radius ratio in $TlCl$?

The crystal $AB$ has a structure similar to $NaCl$. Atoms of $A$ are present at each corner of the cubic unit cell. If all atoms along one of the axes passing through the face centers are removed,what will be the resulting stoichiometry?

In a solid $AB$ having the $NaCl$ structure,$A$ atoms occupy the corners of the cubic unit cell. If all the face-centered atoms along one of the axes are removed,then the resultant stoichiometry of the solid is