If the radius of a solid sphere is doubled while keeping its mass constant,what is the ratio of its moment of inertia about any of its diameters?

Moment of inertia of the rod about an axis passing through the centre and perpendicular to its length is $I_1$. The same rod is bent into a ring and its moment of inertia about the diameter is $I_2$. Then $I_1 / I_2$ is

The moment of inertia of a sphere of mass $M$ and radius $R$ is $I.$ If $M$ is kept constant and a graph is plotted between $I$ and $R,$ then its form would be:

The figure shows an isosceles triangular plate of mass $M$ and base $L$. The angle at the apex is $90^o$. The apex lies at the origin and the base is parallel to the $X$-axis. The moment of inertia of the plate about the $y$-axis is:

$A$ solid spherical ball of density $\rho_{1}$ and a hollow spherical ball of density $\rho_{2}$ have the same outer radius $R$ and the same mass $M$. What is the ratio of the moment of inertia of the hollow sphere to that of the solid sphere about an axis passing through their centers?

Two masses $m_1$ and $m_2$ are placed at a distance $r$ from each other. Find the moment of inertia of the system about an axis passing through the center of mass and perpendicular to the line joining the masses.