If the position vectors of three points $A, B, C$ are $\hat{i}+2\hat{j}+\hat{k}$,$2\hat{i}-\hat{j}+2\hat{k}$ and $\hat{i}+\hat{j}+2\hat{k}$ respectively,then the perpendicular distance of the point $C$ from the line $AB$ is

  • A
    $\sqrt{\frac{3}{11}}$
  • B
    $\sqrt{\frac{4}{11}}$
  • C
    $\sqrt{\frac{6}{11}}$
  • D
    $\sqrt{\frac{8}{11}}$

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