If the points are A(0, 0), B(0, 2), and C(sqr | vedclass

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(B) To determine the type of triangle, we calculate the lengths of the sides using the distance formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.$A

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an equilateral

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(B) To determine the type of triangle, we calculate the lengths of the sides using the distance formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.$AB = \sqrt{(0 - 0)^2 + (2 - 0)^2} = \sqrt{0^2 + 2^2} = \sqrt{4} = 2$.$BC = \sqrt{(\sqrt{3} - 0)^2 + (1 - 2)^2} = \sqrt{(\sqrt{3})^2 + (-1)^2} = \sqrt{3 + 1} = \sqrt{4} = 2$.$AC = \sqrt{(\sqrt{3} - 0)^2 + (1 - 0)^2} = \sqrt{(\sqrt{3})^2 + 1^2} = \sqrt{3 + 1} = \sqrt{4} = 2$.Since $AB = BC = AC = 2$, all three sides are equal.Therefore, $\Delta ABC$ is an equilateral triangle.

If the points are $A(0, 0)$, $B(0, 2)$, and $C(\sqrt{3}, 1)$, then $\Delta ABC$ is $\ldots \ldots \ldots \ldots$ triangle.

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