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(D) Let the radius of the semi-circular protractor be $r \, cm$.The perimeter of a semi-circle is given by the sum of the arc length $(\pi r)$ and the

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$14$

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(D) Let the radius of the semi-circular protractor be $r \, cm$.The perimeter of a semi-circle is given by the sum of the arc length $(\pi r)$ and the diameter $(2r)$.Perimeter $= \pi r + 2r = r(\pi + 2) = 36 \, cm$.Substituting $\pi = \frac{22}{7}$,we get $r(\frac{22}{7} + 2) = 36$.$r(\frac{22 + 14}{7}) = 36 \Rightarrow r(\frac{36}{7}) = 36$.Solving for $r$,we get $r = 7 \, cm$.The diameter of the protractor is $2r = 2 	imes 7 = 14 \, cm$.

If the perimeter of a semi-circular protractor is $36 \, cm$,then its diameter is ...... $cm$?

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