If the numerator of a fraction is increased b | vedclass

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(C) Let the original fraction be $\frac{x}{y}$.According to the problem,the numerator is increased by $150 \%$,so the new numerator is $x + 1.5x = 2.5

Vedclass · Accepted Answer

$\frac{15}{17}$

Vedclass · Answer

(C) Let the original fraction be $\frac{x}{y}$.According to the problem,the numerator is increased by $150 \%$,so the new numerator is $x + 1.5x = 2.5x$.The denominator is increased by $350 \%$,so the new denominator is $y + 3.5y = 4.5y$.The resultant fraction is $\frac{2.5x}{4.5y} = \frac{25}{51}$.Simplifying the ratio: $\frac{25x}{45y} = \frac{25}{51}$.$\frac{5x}{9y} = \frac{25}{51}$.$\frac{x}{y} = \frac{25}{51} 	imes \frac{9}{5} = \frac{5 	imes 3}{17} = \frac{15}{17}$.

If the numerator of a fraction is increased by $150 \%$ and the denominator of the fraction is increased by $350 \%,$ the resultant fraction is $\frac{25}{51},$ what is the original fraction?

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