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(C) Power $P = 64 	ext{ kW} = 64 	imes 10^3 	ext{ W} = 64 	imes 10^3 	ext{ J/s}$.Total energy produced in one hour $(t = 3600 	ext{ s})$ is $E =

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$0.32 	imes 10^{-10} 	ext{ J}$

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(C) Power $P = 64 	ext{ kW} = 64 	imes 10^3 	ext{ W} = 64 	imes 10^3 	ext{ J/s}$.Total energy produced in one hour $(t = 3600 	ext{ s})$ is $E = P 	imes t = 64 	imes 10^3 	imes 3600 	ext{ J} = 2304 	imes 10^5 	ext{ J} = 2.304 	imes 10^8 	ext{ J}$.Number of nuclei $N = 7.2 	imes 10^{18}$.Energy released per fission $\epsilon = E / N = (2.304 	imes 10^8) / (7.2 	imes 10^{18}) 	ext{ J}$.$\epsilon = 0.32 	imes 10^{-10} 	ext{ J}$.

If the number of uranium nuclei required per hour to produce a power of $64 \text{ kW}$ is $7.2 \times 10^{18}$,then the energy released per fission is

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