If the magnitude of a vector overrightarrow{p | vedclass

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Question

(A) The magnitude of a vector $\overrightarrow{p}$ is given by the formula: $|\overrightarrow{p}| = \sqrt{p_x^2 + p_y^2}$.Given, $|\overrightarrow{p}|

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(A) The magnitude of a vector $\overrightarrow{p}$ is given by the formula: $|\overrightarrow{p}| = \sqrt{p_x^2 + p_y^2}$.Given, $|\overrightarrow{p}| = 25 	ext{ units}$ and $p_y = 7 	ext{ units}$.Substituting the values into the formula: $25 = \sqrt{p_x^2 + 7^2}$.Squaring both sides: $25^2 = p_x^2 + 7^2$.$625 = p_x^2 + 49$.$p_x^2 = 625 - 49 = 576$.Taking the square root: $p_x = \sqrt{576} = 24 	ext{ units}$.Therefore, the $x$-component is $24 	ext{ units}$.

If the magnitude of a vector $\overrightarrow{p}$ is $25 \text{ units}$ and its $y$-component is $7 \text{ units}$, then its $x$-component is (in $\text{ units}$)

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