If the magnetic field of a light wave oscilla | vedclass

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Question

(A) The given equation for the magnetic field is $B_y = B_m \sin(kz - \omega t)$.In the wave equation $f(kz - \omega t)$,the term $(kz - \omega t)$ in

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$+z-$ axis,$x-$ axis

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(A) The given equation for the magnetic field is $B_y = B_m \sin(kz - \omega t)$.In the wave equation $f(kz - \omega t)$,the term $(kz - \omega t)$ indicates that the wave is propagating in the positive $z-$ direction.Electromagnetic waves are transverse in nature,meaning the electric field vector $\vec{E}$,the magnetic field vector $\vec{B}$,and the direction of propagation $\vec{k}$ are mutually perpendicular.Since the magnetic field oscillates along the $y-$ axis and the wave propagates along the $z-$ axis,the electric field must oscillate along the $x-$ axis (as $\vec{E} \propto \vec{B} 	imes \vec{k}$).Therefore,the direction of wave travel is the $+z-$ axis and the electric vector oscillates along the $x-$ axis.

If the magnetic field of a light wave oscillates parallel to the $y-$ axis and is given by $B_y = B_m \sin(kz - \omega t)$,the direction of wave travel and the axis along which the electric vector oscillates are:

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